Cross-Term Vanishing #
From the energy form equality + norm inequality, the inner integrals must
agree pointwise. On the overlap region where both u and u-t lie in I,
this forces 1_B(u) = 1_B(u-t) a.e., giving translation invariance.
The null-or-conull theorem then concludes.
Reference: lamportform.tex, Proposition 10, Steps 9–10 (lines 1400–1425).
Section 1: Pointwise norm equality a.e. #
Pointwise norm equality a.e. For each t ∈ (0, 2L):
‖ze(1)(u) - ze(1)(u-t)‖₊² = ‖ze(1_B)(u) - ze(1_B)(u-t)‖₊² + ‖ze(1_{I\B})(u) - ze(1_{I\B})(u-t)‖₊²
a.e. in u.
Proof: apply ae_eq_of_ae_le_of_lintegral_le with the pointwise ≤
from nnnorm_sq_indicator_le and the integral equality from
inner_integral_indicator_everywhere_eq.
Reference: lamportform.tex, Proposition 10, Step 9 (line 1411).
Section 2: Indicator ae invariance on overlap #
Indicator ae invariance on overlap. For each t ∈ (0, 2L),
1_B(u) = 1_B(u-t) a.e. on the overlap I ∩ preimage (·-t) I.
On the overlap, ze(1)(u) = 1 and ze(1)(u-t) = 1, so the LHS norm
vanishes. The pointwise equality then forces both RHS norms to vanish,
giving ze(1_B)(u) = ze(1_B)(u-t), which unfolds to 1_B(u) = 1_B(u-t).
Reference: lamportform.tex, Proposition 10, Step 10 (line 1418).
Section 3: Translation invariance construction #
Translation invariance of 1_B. Constructs the
IndicatorTranslationInvariant hypothesis for inv.B on I = (-L, L)
with ε = 2L.
Reference: lamportform.tex, Proposition 10, Step 10 (line 1420).
Section 4: Null or conull conclusion #
Invariant ideal is null or conull. From the translation invariance
of 1_B, apply the null-or-conull theorem: either volume B = 0
or volume (I \ B) = 0.
Reference: lamportform.tex, Proposition 10, Step 10 (line 1425).